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Physics NEET MCQ
Quiz 7
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Q.1
If nearly 105 coulombs liberate 1 gm equivalent of aluminum, then the amount of aluminum ( equivalent weight 9), deposited through electrolysis in 20 minutes by a current of 50amp will be... [ CBSE PMT 1998]
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a) 0.6 gm
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b) 0.09 gm
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c) 5.4 gm
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d) 10.8 gm
Explanation
mass liberated m=Z(It)=ZQ given m=9 and Q=9×10⁻⁵ ∴ 9=Z×10-5 Z=9×10⁻⁵×50×20×60=5.4gm Answer: (c)
Q.2
In producing chlorine through electrolysis, 100 watt power at 125V is being consumed. How much chlorine per minute is liberated? E.C.E of chlorine is 0.367×10⁻⁶ kg/coulomb [ CBSE-PMT 2006]
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a) 21.3 mg
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b) 24.3 mg
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c)13.6 mg
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d)17.6 mg
Explanation
power P=VI I=P/V=100 /125 Q=I×tQ=(100/125)×60=48 Coulombm=ZQm=0.367×10⁻⁶×48m=17.6 mg Answer:(d)
Q.3
A steady current of 1.5 amp flows through copper voltmeter for 10 minutes. If the electrochemical equivalent of copper is 30×10⁻⁵ g/coulomb, the mass of copper deposited on the electrode will be.. [ CBSE-PMT 2007]
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a)0.50 g
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b) 0.67 g
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c)0.27g
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d)0.40g
Explanation
m=ZItwhere Z is the electrochemical equivalent of copperm=30×10⁻⁵×1.5×10×60m=0.27 gmAnswer: (c)
Q.4
In producing chlorine by electrolysis 100kW power at 125V is being consumed. How much chlorine per minute is liberated? (E.C.E. of chlorine is 0.367×10⁻⁶ kg/C) [ CBSE-PMT 2010]
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a) 1.76×10⁻³ kg
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b) 9.67×10⁻³ kg
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c)17.61×10⁻³ kg
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d)3.67×10⁻³ kg
Explanation
I=P/V=100×103 / 125 A=105 / 60 AE.C.E=0.367×10⁻⁶ kg/CCharge per minute=I×60 CCharge per minutes Q=105 / 125 × 60Q=6×106 / 125 C mass m=ZQ m=0.367×10⁻⁶ × (6×106 / 125)m=17.616×10⁻³kg Answer:(c)
Q.5
What is the energy stored in the capacitor?
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a) 72 µJ
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b) 128µJ
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c) 96mJ
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d) 96MJ
Explanation
VD - VE=IR VD - VE=2 × 4=8 Volts Now energy in capacitor E=½ CV2 E=½ × 4× 10⁻⁶ ×(8) 2=128micro;J Answer: (b)
Q.6
A 40µF capacitor in a defibrillator is charged to 3000V. The energy stored in the capacitor is sent through the patient during a pulse of duration 2ms. The power delivered to the patient is [ AIIMS 2004]
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a) 45 kW
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b) 90 kW
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c) 180 kW
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d) 360 kW
Explanation
Energy in capacitor=(1/2) CV2 Energy in capacitor U=(1/2) ×40×10⁻⁶ ×(3000)2 U=180 J Power=U/times=180/(2×10⁻³=90kW Answer: (b)
0 h : 0 m : 1 s
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