Q.1
Which of the following is non-oscillatory in nature?
  • Under damped & over damped
  • Critically damped & over damped
  • Critically damped & under damped
  • Forced oscillation & over damped
Q.2
If T1 & T2 are the time period for undamped and under damped oscillation respectively, then
  • T₁ < T₂
  • T₁ > T₂
  • T₁ ≥ T₂
  • T₁ = T₂
Q.3
If relaxation time is 3 sec and quality factor isin case of damped oscillation, then angular frequency is ___________ rad/a.
  • 0.5
  • 2
  • 9
  • 18
Q.4
A particle of massgram subjected to a force constant ofdyne/cm and a damping constant ofgm/sec. If it is displaced through 3 cm before being released, then it is ___________ type of motion.
  • Free
  • Under damped
  • Over damped
  • Critically damped
Q.5
Quality factor of an oscillatory object, of mass 3 gram, isIf mass of the object isgram, keeping other factors constant, then the new quality factor is
  • 5
  • 10
  • 20
  • 40
Q.6
Total energy in case of damped oscillation during oscillation
  • increases exponentially .
  • decreases exponentially .
  • remains constant.
  • either increases or remains constant.
Q.7
For a system in oscillation, which of the following is the number of cycles or vibrations in one second?
  • amplitude
  • period
  • frequency
  • revolution
Q.8
Oscillation, which of the following is the time required to complete a cycle of motion?
  • amplitude
  • period
  • frequency
  • revolution
Q.9
In any system in SHM, the restoring force acting on the mass in the system is proportional to
  • the displacement
  • the length of the pendulum
  • the mass
  • the frequency
Q.10
A block of mass m = 4 kg on a frictionless, horizontal table is attached to one end of a spring of force constant k =N/m and undergoes simple harmonic oscillations about its equilibrium position (x =with amplitude A = 6 cm. If the block is at x = 6 cm at time t =then which of the following equations (with x in centimeters and t in seconds) gives the block's position as a function of time?
  • x = 6 sin(10t + 0.5π)
  • x = 6 sin(10πt + 0.5π)
  • x = 6 sin(10πt - 0.5π)
  • x = 6 sin(10t)
  • x = 6 sin(10t - 0.5π)
0 h : 0 m : 1 s